V^'-V^2=5

Lösung

V^{^{'}} - V^{2} = 5

V (t) = tan (5 (t + c_{1})) 5

Schritte zur Lösung

V^{'} (t) - V (t)^{2} = 5

Solve separable ODE:

V (t) = tan (5 (t + c_{1})) 5

V (t) = tan (5 (t + c_{1})) 5

\frac{d y}{d x} = - 5 y

\frac{d y}{d x} = \frac{1 + y ^{2}}{( 1 + x ^{2} ) \cdot x \cdot y}

\frac{d y}{d x} = \frac{y}{5}

\frac{d y}{d t} = 0.07 (100 - y), y (0) = 25

y - 9 \frac{d y}{d t} = 0