(dz)/(dt)=-2e^{t+z}

Lösung

\frac{d z}{d t} = - 2 e^{t + z}

z = - ln (2 e^{t} - c_{1})

Schritte zur Lösung

\frac{d z}{d t} = - 2 e^{t + z}

Solve separable ODE:

z = - ln (2 e^{t} - c_{1})

z = - ln (2 e^{t} - c_{1})

y^{^{'}} - e^{x + y} = 0

y^{^{'}} = - y + 9

y d x + (x - 6) d y = 0, y (7) = 9

(3 y 2 - t 2 y 5) \frac{d y}{d t} + t 2 y 4 = 0

y^{^{'}} = tan (x) y