y^'=(y-1)/(x+3)

Lösung

y^{^{'}} = \frac{y - 1}{x + 3}

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

Schritte zur Lösung

y^{'} (x) = \frac{y - 1}{x + 3}

Solve separable ODE:

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

y^{^{'}} = 5 e^{- x - y}

(t^{2} - 22 t + 85) \frac{d y}{d t} = y

(\frac{d y}{d x}) = (- \frac{1}{( x ^{2} y ^{2} )}), y = 2, x = 1

y^{^{'}} + \frac{1}{3} y = 0

y^{^{'}} = 3 y, y (0) = 14