What is derivative of f(x)=ccos(t)+t^2sin(t) ?

The answer to derivative of f(x)=ccos(t)+t^2sin(t) is (dt)/(dx)=0

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derivative of f(x)=ccos(t)+t^2sin(t)

derivative of

f (x) = c cos (t) + t^{2} sin (t)

\frac{d t}{d x} = 0

Solution steps

f (x) = c cos (t) + t^{2} sin (t)

Treat

t

t (x)

Differentiate both sides:

0 = - c sin (t) \frac{d t}{d x} + 2 t \frac{d t}{d x} sin (t) + cos (t) \frac{d t}{d x} t^{2}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

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\int 34.7 x d x

\int \frac{x + 5}{x ^{2} + 25} d x

What is derivative of f(x)=ccos(t)+t^2sin(t) ?
The answer to derivative of f(x)=ccos(t)+t^2sin(t) is (dt)/(dx)=0