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Beliebt Rechnen >

y^{''}+y=-x^2,y(0)=0,y(1)=1

Lösung

y^{^{''}} + y = - x^{2}, y (0) = 0, y (1) = 1

Lösung

y = - 2 cos (x) + \frac{2 cos ( 1 ) sin ( x )}{sin ( 1 )} - x^{2} + 2

Schritte zur Lösung

y^{''} (x) + y = - x^{2}

Solve linear ODE:

y = - 2 cos (x) + \frac{2 cos ( 1 ) sin ( x )}{sin ( 1 )} - x^{2} + 2

y = - 2 cos (x) + \frac{2 cos ( 1 ) sin ( x )}{sin ( 1 )} - x^{2} + 2

Beliebte Beispiele

y^{''}+y^'-2y=upi(t)-u^2pi(t)

y^{^{''}} + y^{^{'}} - 2 y = u π (t) - u^{2} π (t)

y^{''}+4y^'+3y=-19te^{3t}

y^{^{''}} + 4 y^{^{'}} + 3 y = - 19 t e^{3 t}

y^{''}+4y^'=sin(t)

y^{^{''}} + 4 y^{^{'}} = sin (t)

y^{''}-5y^'+6y=-5e^{3x}

y^{^{''}} - 5 y^{^{'}} + 6 y = - 5 e^{3 x}

y^{''}-2y^'+y=t^2+1

y^{^{''}} - 2 y^{^{'}} + y = t^{2} + 1