t(dQ)/(dt)+Q=t^5ln(t)

解答

t \frac{d Q}{d t} + Q = t^{5} ln (t)

Q = \frac{t ^{5} ln ( t )}{6} - \frac{t ^{5}}{36} + \frac{c _{1}}{t}

求解步骤

t \frac{d Q}{d t} + Q = t^{5} ln (t)

求解线性方程:

Q = \frac{t ^{5} ln ( t )}{6} - \frac{t ^{5}}{36} + \frac{c _{1}}{t}

Q = \frac{t ^{5} ln ( t )}{6} - \frac{t ^{5}}{36} + \frac{c _{1}}{t}

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