y^{''}+6y^'+13y=0,y(0)=-2,y^'(0)=0

Lösung

y^{^{''}} + 6 y^{^{'}} + 13 y = 0, y (0) = - 2, y^{^{'}} (0) = 0

y = e^{- 3 t} (- 2 cos (2 t) - 3 sin (2 t))

Schritte zur Lösung

y^{''} (t) + 6 y^{'} (t) + 13 y = 0

Solve linear ODE:

y = e^{- 3 t} (- 2 cos (2 t) - 3 sin (2 t))

y = e^{- 3 t} (- 2 cos (2 t) - 3 sin (2 t))

y^{^{''}} - 83 y^{^{'}} + α y = 0, y (0) = 1, y^{^{'}} (0) = - 73

x^{^{''}} - 9 x = 0

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (1) = 0, y^{^{'}} (1) = 1

y^{^{''''}} + 3 y^{^{'''}} + 3 y^{^{''}} + y^{^{'}} = 0

y^{^{''}} - 2 y^{^{'}} + y = 0, y (2) = 0, y^{^{'}} (2) = 1