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Beliebt Rechnen >

2y^{''}+4y^'+4y=0

Lösung

2 y^{^{''}} + 4 y^{^{'}} + 4 y = 0

Lösung

y = e^{- t} (c_{1} cos (t) + c_{2} sin (t))

Schritte zur Lösung

2 y^{''} (t) + 4 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = e^{- t} (c_{1} cos (t) + c_{2} sin (t))

y = e^{- t} (c_{1} cos (t) + c_{2} sin (t))

Graph

Beliebte Beispiele

y^{''}-4y^'+y=0,y(0)=3,y^'(0)=5

y^{^{''}} - 4 y^{^{'}} + y = 0, y (0) = 3, y^{^{'}} (0) = 5

y^{''}+2y^'+y=0,y(0)=4,y^'(0)=-2

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 4, y^{^{'}} (0) = - 2

(d^2y)/(dt^2)+6(dy)/(dt)+9y=0

\frac{d ^{2} y}{d t ^{2}} + 6 \frac{d y}{d t} + 9 y = 0

2(d^2y)/(dt^2)+2(dy)/(dt)-y=0

2 \frac{d ^{2} y}{d t ^{2}} + 2 \frac{d y}{d t} - y = 0

y^{^{''}} + n y = 0