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Beliebt Rechnen >

3y^{''}+2y^'+2y=0

Lösung

3 y^{^{''}} + 2 y^{^{'}} + 2 y = 0

Lösung

y = e^{- \frac{t}{3}} (c_{1} cos (\frac{5 t}{3}) + c_{2} sin (\frac{5 t}{3}))

Schritte zur Lösung

3 y^{''} (t) + 2 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = e^{- \frac{t}{3}} (c_{1} cos (\frac{5 t}{3}) + c_{2} sin (\frac{5 t}{3}))

y = e^{- \frac{t}{3}} (c_{1} cos (\frac{5 t}{3}) + c_{2} sin (\frac{5 t}{3}))

Graph

Beliebte Beispiele

y^{''}+2y^'+y=0,y(0)=1,y^'(0)=2

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 1, y^{^{'}} (0) = 2

y^{''}+y^'+5/4 y=0

y^{^{''}} + y^{^{'}} + \frac{5}{4} y = 0

1/8 x^{''}+x^'+2x=0,x(0)=-1,x^'(0)=14

\frac{1}{8} x^{^{''}} + x^{^{'}} + 2 x = 0, x (0) = - 1, x^{^{'}} (0) = 14

x^{''}-6x^'+9x=0

x^{^{''}} - 6 x^{^{'}} + 9 x = 0

y^{^{''}} + 144 y = 0