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Beliebt Rechnen >

2y^{''}-3y^'+2y=0

Lösung

2 y^{^{''}} - 3 y^{^{'}} + 2 y = 0

Lösung

y = e^{\frac{3 t}{4}} (c_{1} cos (\frac{7 t}{4}) + c_{2} sin (\frac{7 t}{4}))

Schritte zur Lösung

2 y^{''} (t) - 3 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = e^{\frac{3 t}{4}} (c_{1} cos (\frac{7 t}{4}) + c_{2} sin (\frac{7 t}{4}))

y = e^{\frac{3 t}{4}} (c_{1} cos (\frac{7 t}{4}) + c_{2} sin (\frac{7 t}{4}))

Graph

Beliebte Beispiele

64y^{'''}+112y^{''}+49y^'=0

64 y^{^{'''}} + 112 y^{^{''}} + 49 y^{^{'}} = 0

y^{''}=5y,y^0=-2,y^2=10

y^{^{''}} = 5 y, y^{0} = - 2, y^{2} = 10

y^{''}+4a^2y^'+y=0

y^{^{''}} + 4 a^{2} y^{^{'}} + y = 0

y^{''}-2y^'+5y=0,y(0)=-1,y^'(0)=3

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (0) = - 1, y^{^{'}} (0) = 3

(d^4y)/(dt^4)-y=0

\frac{d ^{4} y}{d t ^{4}} - y = 0