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Beliebt Rechnen >

y^{''}+2y^'+26y=0,y(0)=2,y^'(0)=-1

Lösung

y^{^{''}} + 2 y^{^{'}} + 26 y = 0, y (0) = 2, y^{^{'}} (0) = - 1

Lösung

y = e^{- t} (2 cos (5 t) + \frac{1}{5} sin (5 t))

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + 26 y = 0

Solve linear ODE:

y = e^{- t} (2 cos (5 t) + \frac{1}{5} sin (5 t))

y = e^{- t} (2 cos (5 t) + \frac{1}{5} sin (5 t))

Graph

Beliebte Beispiele

y^{''}-2y^'+2y=0,y(pi/2)=1,y(0)=1

y^{^{''}} - 2 y^{^{'}} + 2 y = 0, y (\frac{π}{2}) = 1, y (0) = 1

y^{^{''}} = 6 y

y^{''}+6y^'+9y=0,y(0)=-4,y^'(0)=14

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (0) = - 4, y^{^{'}} (0) = 14

3y^{''}-24y^'+48y=0

3 y^{^{''}} - 24 y^{^{'}} + 48 y = 0

4(d^2y)/(dt^2)-y=0

4 \frac{d ^{2} y}{d t ^{2}} - y = 0