y^{''}+(-2)y^'+y=0

Lösung

y^{^{''}} + (- 2) y^{^{'}} + y = 0

y = c_{1} e^{t} + c_{2} t e^{t}

Schritte zur Lösung

y^{''} (t) + (- 2) y^{'} (t) + y = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} t e^{t}

y = c_{1} e^{t} + c_{2} t e^{t}

y^{^{''}} + 4 y = 0, y (0) = 3, y^{^{'}} (0) = 5

625 y^{^{''''}} = 81 y

y^{^{''}} + 4 y = 0, y (0) = 2, y^{^{'}} (0) = - 1

y^{^{''''}} + y^{^{''}} - 12 y = 0

y^{^{''}} - 225 y = 0