2y^{''}-y^'=0

Lösung

2 y^{^{''}} - y^{^{'}} = 0

y = c_{1} e^{\frac{t}{2}} + c_{2}

Schritte zur Lösung

2 y^{''} (t) - y^{'} (t) = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{2}} + c_{2}

y = c_{1} e^{\frac{t}{2}} + c_{2}

y^{^{''}} + 4 y^{^{'}} + 20 y = 0, y (0) = 2, y^{^{'}} (0) = - 3

y^{^{''}} + 2 y^{^{'}} + y = 0, y^{^{'}} (0) = 8, y (1) = 6

2 y^{^{''}} + 8 y^{^{'}} + 80 y = 0, y (0) = 0

y^{^{''}} - 2 y^{^{'}} + 10 y = 0, y (0) = 0, y^{^{'}} (0) = 4

8 x^{^{''}} + x = 0