解答
100y′′+60y′+90y=0,y(1)=9,y′(1)=2
解答
y=e−103t3cos(109)(−sin(109)+3cos(109)+3sin2(109)sec(109)+cos(109)sec(109)sin(109))(27e103(−sin(109)+3cos(109)+3sin2(109)sec(109)+cos(109)sec(109)sin(109))−sin(109)(20e103+27e103sec(109)cos(109)+81e103sec(109)sin(109)))cos(109t)+3(−sin(109)+3cos(109)+3sin2(109)sec(109)+cos(109)sec(109)sin(109))(20e103+27e103sec(109)cos(109)+81e103sec(109)sin(109))sin(109t)
求解步骤
100y′′(t)+60y′(t)+90y=0
求解线性方程:y=e−103t3cos(109)(−sin(109)+3cos(109)+3sin2(109)sec(109)+cos(109)sec(109)sin(109))(27e103(−sin(109)+3cos(109)+3sin2(109)sec(109)+cos(109)sec(109)sin(109))−sin(109)(20e103+27e103sec(109)cos(109)+81e103sec(109)sin(109)))cos(109t)+3(−sin(109)+3cos(109)+3sin2(109)sec(109)+cos(109)sec(109)sin(109))(20e103+27e103sec(109)cos(109)+81e103sec(109)sin(109))sin(109t)
y=e−103t3cos(109)(−sin(109)+3cos(109)+3sin2(109)sec(109)+cos(109)sec(109)sin(109))(27e103(−sin(109)+3cos(109)+3sin2(109)sec(109)+cos(109)sec(109)sin(109))−sin(109)(20e103+27e103sec(109)cos(109)+81e103sec(109)sin(109)))cos(109t)+3(−sin(109)+3cos(109)+3sin2(109)sec(109)+cos(109)sec(109)sin(109))(20e103+27e103sec(109)cos(109)+81e103sec(109)sin(109))sin(109t)