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Beliebt Rechnen >

y^{''}+2y^'+10y=0,y(0)=e^{-pi/6}

Lösung

y^{^{''}} + 2 y^{^{'}} + 10 y = 0, y (0) = e^{- \frac{π}{6}}

Lösung

y = e^{- t} (\frac{1}{e ^{\frac{π}{6}}} cos (3 t) + c_{2} sin (3 t))

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + 10 y = 0

Solve linear ODE:

y = e^{- t} (\frac{1}{e ^{\frac{π}{6}}} cos (3 t) + c_{2} sin (3 t))

y = e^{- t} (\frac{1}{e ^{\frac{π}{6}}} cos (3 t) + c_{2} sin (3 t))

Graph

Beliebte Beispiele

(d^3y)/(dt^3)-(d^2y)/(dt^2)=0

\frac{d ^{3} y}{d t ^{3}} - \frac{d ^{2} y}{d t ^{2}} = 0

y^{''}+4y=0,y(0)=0,y^'(0)= 18/5

y^{^{''}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = \frac{18}{5}

64y^{''}+16y^'+50y=0

64 y^{^{''}} + 16 y^{^{'}} + 50 y = 0

x^{''}-(npi)^2x=0

x^{^{''}} - (nπ)^{2} x = 0

linear y^{''}-3y^'-4y=0

l in e a r y^{^{''}} - 3 y^{^{'}} - 4 y = 0