1/8 y^{''}+4y^'+12y=0

Lösung

\frac{1}{8} y^{^{''}} + 4 y^{^{'}} + 12 y = 0

y = c_{1} e^{4 (10 - 4) t} + c_{2} e^{- 4 (4 + 10) t}

Schritte zur Lösung

\frac{1}{8} y^{''} (t) + 4 y^{'} (t) + 12 y = 0

Solve linear ODE:

y = c_{1} e^{4 (10 - 4) t} + c_{2} e^{- 4 (4 + 10) t}

y = c_{1} e^{4 (10 - 4) t} + c_{2} e^{- 4 (4 + 10) t}

36 y^{^{''}} - 84 y^{^{'}} + 49 y = 0

3 y^{^{'''}} + y^{^{''}} + y^{^{'}} - 2 y = 0

20 y^{^{''}} + 200 y^{^{'}} + 520 y = 0

l in e a r y^{^{''}} - 6 y^{^{'}} + 9 y = 0

- a y^{^{''}} = - k y