-3y^{''}+1/12 y=0

Lösung

- 3 y^{^{''}} + \frac{1}{12} y = 0

y = c_{1} e^{\frac{t}{6}} + c_{2} e^{- \frac{t}{6}}

Schritte zur Lösung

- 3 y^{''} (t) + \frac{1}{12} y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{6}} + c_{2} e^{- \frac{t}{6}}

y = c_{1} e^{\frac{t}{6}} + c_{2} e^{- \frac{t}{6}}

\frac{1}{8} y^{^{''}} + 4 y^{^{'}} + 28 y = 0, y (0) = 0, y^{^{'}} (0) = 8

\frac{d ^{4} y}{d x ^{4}} - 2 \frac{d ^{2} y}{d x ^{2}} - 8 y = 0

3 y^{^{''}} + 12 y = 0, y (0) = 8, y^{^{'}} (0) = 6

y^{^{''}} + 12 y^{^{'}} + 38 y = 0, y (0) = 2, y^{^{'}} (0) = 0

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 4, y^{^{'}} (0) = - 1