y^{''}-y^'-12y=0,y(1)=0y^'(1)

Lösung

y^{^{''}} - y^{^{'}} - 12 y = 0, y (1) = 0 y^{^{'}} (1)

y = c_{1} e^{4 t} + c_{2} e^{- 3 t}

Schritte zur Lösung

y^{''} (t) - y^{'} (t) - 12 y = 0

Solve linear ODE:

y = c_{1} e^{4 t} + c_{2} e^{- 3 t}

y = c_{1} e^{4 t} + c_{2} e^{- 3 t}

l in e a r y^{^{'''}} - 5 y^{^{''}} - 4 y^{^{'}} + 20 y = 0

y^{^{''}} + 4 y^{^{'}} + 4 y = 0, y (0) = 2, y^{^{'}} (0) = - 3

\frac{d ^{2} y}{d x ^{2}} + 4 y = 0, y = - cos (2 x)

y^{^{'''}} + 2 y^{^{''}} - 11 y^{^{'}} - 12 y = 0

y^{^{''}} - 5 y^{^{'}} - 6 y = 0, y (0) = x, y^{^{'}} (0) = 4