3y^{'''}+4y^{''}=0

Lösung

3 y^{^{'''}} + 4 y^{^{''}} = 0

y = c_{1} e^{- \frac{4 t}{3}} + c_{2} + c_{3} t

Schritte zur Lösung

3 y^{'''} (t) + 4 y^{''} (t) = 0

Solve linear ODE:

y = c_{1} e^{- \frac{4 t}{3}} + c_{2} + c_{3} t

y = c_{1} e^{- \frac{4 t}{3}} + c_{2} + c_{3} t

100 y^{^{''}} + 40 y^{^{'}} - 45 y = 0

2 y^{^{''}} + 6 y^{^{'}} - \frac{9 y}{2} = 0

2 y^{^{''}} + 3 y^{^{'}} - 3 y = 0

\frac{d ^{2} y}{d x ^{2}} + 4 y = 0, y = 0

9 y^{^{''}} + 4 y^{^{'}} = - 5 y