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Beliebt Rechnen >

x^{''}+25x=0,x(0)=0.6,x^'(0)=1

Lösung

x^{^{''}} + 25 x = 0, x (0) = 0.6, x^{^{'}} (0) = 1

Lösung

x = 0.6 cos (5 t) + \frac{1}{5} sin (5 t)

Schritte zur Lösung

x^{''} (t) + 25 x = 0

Solve linear ODE:

x = 0.6 cos (5 t) + \frac{1}{5} sin (5 t)

x = 0.6 cos (5 t) + \frac{1}{5} sin (5 t)

Graph

Beliebte Beispiele

-a*y^{''}+y^'=0,y(0)=1,y(1)=0

- a \cdot y^{^{''}} + y^{^{'}} = 0, y (0) = 1, y (1) = 0

16y^{''}+9y^'=0

16 y^{^{''}} + 9 y^{^{'}} = 0

y^{''}+4y^'+5y=0,y(0)=0,y^'(0)=0

y^{^{''}} + 4 y^{^{'}} + 5 y = 0, y (0) = 0, y^{^{'}} (0) = 0

49y^{''}+42y^'+9y=0,y(0)=7,y^'(0)=1

49 y^{^{''}} + 42 y^{^{'}} + 9 y = 0, y (0) = 7, y^{^{'}} (0) = 1

y^{''''}-6y^{'''}+5y^{''}=0

y^{^{''''}} - 6 y^{^{'''}} + 5 y^{^{''}} = 0