y^{''}+6y^'+9y=0,y^'0=10,y^0=2

Lösung

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y^{^{'}} 0 = 10, y^{0} (0) = 2

y = c_{1} e^{- 3 t} + c_{2} t e^{- 3 t}

Schritte zur Lösung

y^{''} (t) + 6 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = c_{1} e^{- 3 t} + c_{2} t e^{- 3 t}

y = c_{1} e^{- 3 t} + c_{2} t e^{- 3 t}

\frac{d ^{2} f}{d x ^{2}} + a f (x) = 0

1296 y^{^{''}} + 72 y^{^{'}} + y = 0, y (0) = 7, y^{^{'}} (0) = 5

y^{^{''}} - 16 y = 0, y (0) = 13, y^{^{'}} (0) = 20

y^{^{''}} + 6 y^{^{'}} + 5 y = 0, y (0) = 0, y^{^{'}} (0) = 0

2 y^{^{'''}} + 7 y^{^{''}} - 17 y^{^{'}} - 10 y = 0