What is the solution for derivative of y=2e^x ?

The solution for derivative of y=2e^x is y=2e^x+c_{1}

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Find the Derivative - d/dx y=2e^x

\frac{d}{d x} y = 2 e^{x}

y = 2 e^{x} + c_{1}

Solution steps

\frac{d y}{d x} = 2 e^{x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 2 e^{x} d x

\int 2 e^{x} d x = 2 e^{x} + c_{1}

y = 2 e^{x} + c_{1}

\frac{d}{d x} (x cos (x))

\frac{d}{d x} (cos (x) sec (x))

\frac{d}{d x} (e^{3 x})

(4, 0), (0, 3)

x \to \infty lim (\frac{x}{4})

What is the solution for derivative of y=2e^x ?
The solution for derivative of y=2e^x is y=2e^x+c_{1}