What is the solution for derivative of y=sin(x) ?

The solution for derivative of y=sin(x) is y=-cos(x)+c_{1}

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Find the Derivative - d/dx y=sin(x)

\frac{d}{d x} y = sin (x)

y = - cos (x) + c_{1}

Solution steps

\frac{d y}{d x} = sin (x)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int sin (x) d x

\int sin (x) d x = - cos (x) + c_{1}

y = - cos (x) + c_{1}

f (x) = cos (2 x)

\frac{d}{d y} (- 2 y)

\frac{d}{d x} (2 x)

\frac{d}{d x} (sin (3 x))

\frac{d}{d x} (2 cos (x))

What is the solution for derivative of y=sin(x) ?
The solution for derivative of y=sin(x) is y=-cos(x)+c_{1}