What is the derivative derivative of 1/((2x)) ?

The derivative derivative of 1/((2x)) is -1/(2x^2)

What is the first derivative derivative of 1/((2x)) ?

The first derivative derivative of 1/((2x)) is -1/(2x^2)

derivative of

\frac{d}{d x} (\frac{1}{( 2 x )})

- \frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{( 2 x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{1}{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{1}{2 x ^{2}}

= - \frac{1}{2 x ^{2}}

\frac{d}{d x} y = \frac{5}{x}

\frac{d}{d x} y = \frac{( sec ( x ) )}{x}

\frac{d}{d x} (tan (2 x))

\frac{d}{d x} (1 - sin (x))

f (x) = cos (2 x)

What is the derivative derivative of 1/((2x)) ?
The derivative derivative of 1/((2x)) is -1/(2x^2)
What is the first derivative derivative of 1/((2x)) ?
The first derivative derivative of 1/((2x)) is -1/(2x^2)