What is the derivative derivative of 2xy ?

The derivative derivative of 2xy is 2(y+x(dy)/(dx))

What is the first derivative derivative of 2xy ?

The first derivative derivative of 2xy is 2(y+x(dy)/(dx))

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derivative of

\frac{d}{d x} (2 x y)

2 (y + x \frac{d y}{d x})

Solution steps

\frac{d}{d x} (2 x y)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x y)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = y

= 2 (\frac{d x}{d x} y + \frac{d y}{d x} x)

\frac{d x}{d x} = 1

= 2 (1 \cdot y + \frac{d y}{d x} x)

Simplify

= 2 (y + x \frac{d y}{d x})

f (x) = x^{2} + 2 x, 0 < x < 6

\frac{d}{d x} (tan (3 x))

\frac{d}{d x} f (x) = e^{4 x}

\frac{d}{d x} y = 6 x

\frac{d}{d x} (7 x)

What is the derivative derivative of 2xy ?
The derivative derivative of 2xy is 2(y+x(dy)/(dx))
What is the first derivative derivative of 2xy ?
The first derivative derivative of 2xy is 2(y+x(dy)/(dx))