What is the solution for derivative of y=4x ?

The solution for derivative of y=4x is y=2x^2+c_{1}

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Find the Derivative - d/dx y=4x

\frac{d}{d x} y = 4 x

y = 2 x^{2} + c_{1}

Solution steps

\frac{d y}{d x} = 4 x

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 4 x d x

\int 4 x d x = 2 x^{2} + c_{1}

y = 2 x^{2} + c_{1}

\frac{d}{d x} y = 2 x^{2}

\frac{d}{d x} (cot (2 x))

\frac{d}{d x} (1 - cos (x))

\int (\frac{1}{( sin ( 2 x ) )}) d x

\frac{d}{d x} (e^{x} - 3)

What is the solution for derivative of y=4x ?
The solution for derivative of y=4x is y=2x^2+c_{1}