What is the derivative derivative of 2sec^2(xtan(x)) ?

The derivative derivative of 2sec^2(xtan(x)) is -4sec^2(x)+6sec^4(x)

What is the first derivative derivative of 2sec^2(xtan(x)) ?

The first derivative derivative of 2sec^2(xtan(x)) is -4sec^2(x)+6sec^4(x)

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derivative of

\frac{d}{d x} (2 sec^{2} (x) tan (x))

- 4 sec^{2} (x) + 6 sec^{4} (x)

Solution steps

\frac{d}{d x} (2 sec^{2} (x) tan (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sec^{2} (x) tan (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sec^{2} (x), g = tan (x)

= 2 (\frac{d}{d x} (sec^{2} (x)) tan (x) + \frac{d}{d x} (tan (x)) sec^{2} (x))

\frac{d}{d x} (sec^{2} (x)) = 2 sec^{2} (x) tan (x)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 2 (2 sec^{2} (x) tan (x) tan (x) + sec^{2} (x) sec^{2} (x))

Simplify

2 (2 sec^{2} (x) tan (x) tan (x) + sec^{2} (x) sec^{2} (x)) : - 4 sec^{2} (x) + 6 sec^{4} (x)

= - 4 sec^{2} (x) + 6 sec^{4} (x)

\frac{d}{d x} (\frac{6}{x})

\frac{d}{d x} (\frac{1}{( x ^{2} )})

\frac{d y}{d x} y = \frac{x + 1}{x}

\int (e^{2 x} x^{2}) d x

n = 1 \sum \infty (\frac{- 1}{3})^{n - 1}

What is the derivative derivative of 2sec^2(xtan(x)) ?
The derivative derivative of 2sec^2(xtan(x)) is -4sec^2(x)+6sec^4(x)
What is the first derivative derivative of 2sec^2(xtan(x)) ?
The first derivative derivative of 2sec^2(xtan(x)) is -4sec^2(x)+6sec^4(x)