What is the solution for derivative of y=3e^x ?

The solution for derivative of y=3e^x is y=3e^x+c_{1}

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Find the Derivative - d/dx y=3e^x

\frac{d}{d x} y = 3 e^{x}

y = 3 e^{x} + c_{1}

Solution steps

\frac{d y}{d x} = 3 e^{x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 3 e^{x} d x

\int 3 e^{x} d x = 3 e^{x} + c_{1}

y = 3 e^{x} + c_{1}

\frac{d}{d t} (2 t)

\frac{d}{d x} f (x) = e^{6 x}

f (x) = sin (2 x)

f (x) = \frac{1}{( x ^{3} )}

\frac{d}{d x} (e^{\frac{1}{x}})

What is the solution for derivative of y=3e^x ?
The solution for derivative of y=3e^x is y=3e^x+c_{1}