What is the derivative derivative of 2cos(2x) ?

The derivative derivative of 2cos(2x) is -4sin(2x)

What is the first derivative derivative of 2cos(2x) ?

The first derivative derivative of 2cos(2x) is -4sin(2x)

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derivative of

\frac{d}{d x} (2 cos (2 x))

- 4 sin (2 x)

Solution steps

\frac{d}{d x} (2 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 (- sin (2 x) \cdot 2)

Simplify

= - 4 sin (2 x)

\frac{d}{d x} (\frac{1}{( e ^{x} )})

\frac{d y}{d x} y = x sin (x)

\frac{1}{( y ^{2} )}

\frac{d}{d x} \frac{1}{( ( 1 - x ) ^{2} )}

f (x) = cos (x)

What is the derivative derivative of 2cos(2x) ?
The derivative derivative of 2cos(2x) is -4sin(2x)
What is the first derivative derivative of 2cos(2x) ?
The first derivative derivative of 2cos(2x) is -4sin(2x)