What is the solution for derivative of y= 1/((x-1)) ?

The solution for derivative of y= 1/((x-1)) is y=ln(x-1)+c_{1}

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Find the Derivative - d/dx y=1/(x-1)

\frac{d}{d x} y = \frac{1}{( x - 1 )}

y = ln (x - 1) + c_{1}

Solution steps

\frac{d y}{d x} = \frac{1}{( x - 1 )}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{1}{x - 1} d x

\int \frac{1}{x - 1} d x = ln (x - 1) + c_{1}

y = ln (x - 1) + c_{1}

\frac{d}{d x} (arccsc (x))

f = \frac{1}{x}

\frac{d}{d x} f (x) = e^{- a x}

\frac{d}{d x} y = cos (2 x)

y = \frac{1}{2 x - 4}

What is the solution for derivative of y= 1/((x-1)) ?
The solution for derivative of y= 1/((x-1)) is y=ln(x-1)+c_{1}