What is the solution for derivative of y=sin(1/x) ?

The solution for derivative of y=sin(1/x) is y=xsin(1/x)-\Ci(1/x)+c_{1}

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Find the Derivative - d/dx y=sin(1/x)

\frac{d}{d x} y = sin (\frac{1}{x})

y = x sin (\frac{1}{x}) - Ci (\frac{1}{x}) + c_{1}

Solution steps

\frac{d y}{d x} = sin (\frac{1}{x})

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int sin (\frac{1}{x}) d x

y = x sin (\frac{1}{x}) - Ci (\frac{1}{x}) + c_{1}

\frac{d}{d x} (\frac{( sin ( x ) )}{x})

\frac{d y}{d x} y = sec (x)

\frac{d}{d x} (\frac{1}{( ln ( x ) )})

\frac{d}{d x} (ln (2))

\frac{d}{d x} (ln (3))

What is the solution for derivative of y=sin(1/x) ?
The solution for derivative of y=sin(1/x) is y=xsin(1/x)-\Ci(1/x)+c_{1}