(dy}{dx}=\frac{x^2)/9+7/9

Lösung

\frac{d y}{d x} = \frac{x ^{2}}{9} + \frac{7}{9}

y = \frac{x ^{3}}{27} + \frac{7}{9} x + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = \frac{x ^{2}}{9} + \frac{7}{9}

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = \frac{x ^{2}}{9} + \frac{7}{9}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{x ^{2}}{9} + \frac{7}{9} d x

\int \frac{x ^{2}}{9} + \frac{7}{9} d x = \frac{x ^{3}}{27} + \frac{7}{9} x + c_{1}

y = \frac{x ^{3}}{27} + \frac{7}{9} x + c_{1}

\frac{d}{d x} ((cos (x))^{2} - 2 sin (x))

x \to \infty lim (\frac{ln ( x ^{5} )}{13 x})

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