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Beliebt Rechnen >

ty^'+(t+1)y=t,y(ln(2))=1

Lösung

t y^{^{'}} + (t + 1) y = t, y (ln (2)) = 1

Lösung

y = 1 - \frac{1}{t} + \frac{2}{e ^{t} t}

Schritte zur Lösung

t y^{'} (t) + (t + 1) y = t

Solve linear ODE:

y = 1 - \frac{1}{t} + \frac{2}{e ^{t} t}

y = 1 - \frac{1}{t} + \frac{2}{e ^{t} t}

Graph

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