sum from y=0 to infinity of 2^{-2-y+x}

解答

y = 0 \sum \infty 2^{- 2 - y + x}

收敛

求解步骤

n = 0 \sum \infty 2^{- 2 - n + x}

使用级数比值审敛法:

收敛

= 收敛

\frac{\partial}{\partial y} (x 1 + y^{5})

\int t e^{- a t} d t

6 t^{2} y^{^{''}} - 12 y = 14 t^{2} - 1

\int 4 x^{3} - 10 x d x

\int \frac{4 t ^{3} - t ^{2} + 16 t}{t ^{2} + 4} d t