derivative f(x)=csc^7(2x^pi+pi^3)

解

導関数

f (x) = csc^{7} (2 x^{π} + π^{3})

- 14 π x^{π - 1} csc^{7} (2 x^{π} + π^{3}) cot (2 x^{π} + π^{3})

解答ステップ

\frac{d}{d x} (csc^{7} (2 x^{π} + π^{3}))

連鎖法則を適用:

7 (csc (2 x^{π} + π^{3}))^{6} \frac{d}{d x} (csc (2 x^{π} + π^{3}))

= 7 (csc (2 x^{π} + π^{3}))^{6} \frac{d}{d x} (csc (2 x^{π} + π^{3}))

\frac{d}{d x} (csc (2 x^{π} + π^{3})) = - cot (2 x^{π} + π^{3}) csc (2 x^{π} + π^{3}) \cdot 2 π x^{π - 1}

= 7 (csc (2 x^{π} + π^{3}))^{6} (- cot (2 x^{π} + π^{3}) csc (2 x^{π} + π^{3}) \cdot 2 π x^{π - 1})

簡素化

7 csc^{6} (2 x^{π} + π^{3}) (- cot (2 x^{π} + π^{3}) csc (2 x^{π} + π^{3}) \cdot 2 π x^{π - 1}) : - 14 π x^{π - 1} csc^{7} (2 x^{π} + π^{3}) cot (2 x^{π} + π^{3})

= - 14 π x^{π - 1} csc^{7} (2 x^{π} + π^{3}) cot (2 x^{π} + π^{3})