derivative of 9arctan(x)

解答

\frac{d}{d x} (9 arctan (x))

\frac{9}{x ^{2} + 1}

求解步骤

\frac{d}{d x} (9 arctan (x))

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (arctan (x))

使用常见微分定则:

\frac{d}{d x} (arctan (x)) = \frac{1}{x ^{2} + 1}

= 9 \cdot \frac{1}{x ^{2} + 1}

化简

9 \cdot \frac{1}{x ^{2} + 1} : \frac{9}{x ^{2} + 1}

= \frac{9}{x ^{2} + 1}

x \to 0 lim (6 - \frac{1}{x ^{3}})

\int \frac{3 x + ( 2 )}{( x )} d x

\int 2 x^{4} ln (x) d x

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d er i v a t i v e cos ((π x)^{3})