inverselaplace e^{-pis} 2/(s^3)

Lösung

inverse laplace transformation

e^{- π s} \frac{2}{s ^{3}}

H (t - π) (t - π)^{2}

Schritte zur Lösung

L^{- 1} {e^{- π s} \frac{2}{s ^{3}}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

H (t)

Heaviside (Schritt) Funktion ist

= H (t - π) L^{- 1} {\frac{2}{s ^{3}}} (t - π)

L^{- 1} {\frac{2}{s ^{3}}} : t^{2}

= H (t - π) (t - π)^{2}

d er i v a t i v e 2 x csc (x) - x^{2} cot (x) csc (x)

\int_{3}^{\infty} e^{- \frac{x}{4}} d x

\frac{\partial}{\partial x} (9 cos (y e^{x y}) sin (x))

a re a x^{2} - 19, 18 x

\frac{\partial}{\partial x} (1 + x \cdot ln (x y - 5))