derivative (sin(θ))/3+c/θ

解

導関数

\frac{sin ( θ )}{3} + \frac{c}{θ}

\frac{1}{3} cos (θ) - \frac{c}{θ ^{2}}

解答ステップ

\frac{d}{d θ} (\frac{sin ( θ )}{3} + \frac{c}{θ})

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (\frac{sin ( θ )}{3}) + \frac{d}{d θ} (\frac{c}{θ})

\frac{d}{d θ} (\frac{sin ( θ )}{3}) = \frac{1}{3} cos (θ)

\frac{d}{d θ} (\frac{c}{θ}) = - \frac{c}{θ ^{2}}

= \frac{1}{3} cos (θ) - \frac{c}{θ ^{2}}