6y^{''}+y^'=0

Lösung

6 y^{^{''}} + y^{^{'}} = 0

y = c_{1} + c_{2} e^{- \frac{t}{6}}

Schritte zur Lösung

6 y^{''} (t) + y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{t}{6}}

y = c_{1} + c_{2} e^{- \frac{t}{6}}

\frac{d}{d x} (\frac{π}{2})

\int 5 e^{- 4 x + 8} - 5 d x

\int y e^{- 2 y} d y

\frac{d}{d t} (\frac{1}{2} t^{2} + t)

f (x) = 3^{- 6 x + 6}