What is the integral from 1 to 5 of sqrt(1+(4)^2) ?

The integral from 1 to 5 of sqrt(1+(4)^2) is 4sqrt(17)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 5 of sqrt(1+(4)^2)

\int_{1}^{5} 1 + (4)^{2} d x

417

Decimal Notation

16.49242 \dots

Solution steps

\int_{1}^{5} 1 + 4^{2} d x

Integral of a constant:

\int a d x = a x

= [1 + 4^{2} x]_{1}^{5}

Simplify

= [17 x]_{1}^{5}

Compute the boundaries:

417

= 417

\frac{d}{d x} (\frac{3}{2 x})

x \to 1 lim (- 3 a x + b)

\frac{d}{d x} ((13 x^{2} - 26 x + 26) e^{x})

\frac{d}{d x} (e^{\frac{x}{2}} + 4 x)

\int_{0}^{4.5} 100 x d x

What is the integral from 1 to 5 of sqrt(1+(4)^2) ?
The integral from 1 to 5 of sqrt(1+(4)^2) is 4sqrt(17)