y^{''}+2y=-18x^2e^{2x}

Lösung

y^{^{''}} + 2 y = - 18 x^{2} e^{2 x}

y = c_{1} cos (2 x) + c_{2} sin (2 x) - 3 x^{2} e^{2 x} + 4 x e^{2 x} - \frac{5}{3} e^{2 x}

Schritte zur Lösung

y^{''} (x) + 2 y = - 18 x^{2} e^{2 x}

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) - 3 x^{2} e^{2 x} + 4 x e^{2 x} - \frac{5}{3} e^{2 x}

y = c_{1} cos (2 x) + c_{2} sin (2 x) - 3 x^{2} e^{2 x} + 4 x e^{2 x} - \frac{5}{3} e^{2 x}

\int_{1}^{0} - 9 x d x

y^{^{''}} - 4 y^{^{'}} - 12 y = t e^{4 t}

\int_{- 2}^{2} \frac{1}{2} (4^{2} - x^{4}) d x

\int_{0}^{1} 1 + 3 x d x

l a pl a ce t r an s f or m - 3 sin (3 t)