integral from 2 to 4 of 2x^2-3x+1

Lösung

\int_{2}^{4} 2 x^{2} - 3 x + 1 d x

\frac{64}{3}

Dezimale

21.33333 \dots

Schritte zur Lösung

\int_{2}^{4} 2 x^{2} - 3 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} 2 x^{2} d x - \int_{2}^{4} 3 x d x + \int_{2}^{4} 1 d x

\int_{2}^{4} 2 x^{2} d x = \frac{112}{3}

\int_{2}^{4} 3 x d x = 18

\int_{2}^{4} 1 d x = 2

= \frac{112}{3} - 18 + 2

Vereinfache

\frac{112}{3} - 18 + 2 : \frac{64}{3}

= \frac{64}{3}

\frac{\partial}{\partial x} (cos (x ln (y)))

x \to + 0 + lim (\frac{36 - 4 x ^{2}}{x})

\int 2 x 2 x - 1 d x

\frac{d}{d x} (\frac{1}{6 x ^{\frac{5}{6}}})

s l o p e (1, 1), (4, - \frac{1}{2})