y^'= y/x+tan(y/x)

Lösung

y^{^{'}} = \frac{y}{x} + tan (\frac{y}{x})

y = arcsin (c_{1} x) x + 2 πn x, y = π x + arcsin (- c_{1} x) x + 2 πn x

Schritte zur Lösung

y^{'} (x) = \frac{y}{x} + tan (\frac{y}{x})

Solve using substitution:

y = arcsin (c_{1} x) x + 2 πn x, y = π x + arcsin (- c_{1} x) x + 2 πn x

y = arcsin (c_{1} x) x + 2 πn x, y = π x + arcsin (- c_{1} x) x + 2 πn x

4 y^{^{''}} + 9 y = 0, y (0) = 2, y^{^{'}} (0) = 3

\frac{d}{d x} (a (2 e^{- 3 x} x - 3 e^{- 3 x} x^{2}))

\frac{\partial}{\partial x} (- sin (4 x))

d er i v a t i v e f (x) = x^{2} + 2 x + 3

\int 4 \frac{x}{( x + 2 ) ^{(\frac{1}{4})}} d x