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tangent f(x)=6x^2-10x+4,\at x=1

解答

切线

f (x) = 6 x^{2} - 10 x + 4, at x = 1

解答

y = 2 x - 2

求解步骤

找到切点:

(1, 0)

计算

f (x) = 6 x^{2} - 10 x + 4

的斜率:

\frac{df ( x )}{d x} = 12 x - 10

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

找到斜率 m=

2

且穿过

(1, 0)

的直线:

y = 2 x - 2

y = 2 x - 2

作图

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