derivative of log_{2}(x-1-2)

Lösung

\frac{d}{d x} (lo g_{2} (x - 1) - 2)

\frac{1}{ln ( 2 ) ( x - 1 )}

Schritte zur Lösung

\frac{d}{d x} (lo g_{2} (x - 1) - 2)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (lo g_{2} (x - 1)) - \frac{d}{d x} (2)

\frac{d}{d x} (lo g_{2} (x - 1)) = \frac{1}{ln ( 2 ) ( x - 1 )}

\frac{d}{d x} (2) = 0

= \frac{1}{ln ( 2 ) ( x - 1 )} - 0

Vereinfache

= \frac{1}{ln ( 2 ) ( x - 1 )}

d er i v a t i v e y = x^{2} e^{x} - 2 x e^{x} + 6 e^{x}

t an g e n t f (x) = 16 x, at x = 16

s im pl i f y (2 x^{- 2} + 3)^{- 3}

\int \frac{1}{1 0 ^{5} x - x ^{2}} d x

\int 4 x^{\frac{1}{3}} + 2 x^{- \frac{1}{3}} d x