integral of (x^{3/2}+2x+1)

解

\int (x^{\frac{3}{2}} + 2 x + 1) d x

\frac{2}{5} x^{\frac{5}{2}} + x^{2} + x + C

解答ステップ

\int x^{\frac{3}{2}} + 2 x + 1 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{3}{2}} d x + \int 2 x d x + \int 1 d x

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

\int 2 x d x = x^{2}

\int 1 d x = x

= \frac{2}{5} x^{\frac{5}{2}} + x^{2} + x

定数を解答に追加する

= \frac{2}{5} x^{\frac{5}{2}} + x^{2} + x + C