What is the integral from 1 to 2 of xsqrt(x^2-1) ?

The integral from 1 to 2 of xsqrt(x^2-1) is square root of 3

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integral from 1 to 2 of xsqrt(x^2-1)

\int_{1}^{2} x x^{2} - 1 d x

3

Decimal Notation

1.73205 \dots

Solution steps

\int_{1}^{2} x x^{2} - 1 d x

Apply u-substitution

: \int_{0}^{3} u^{2} d u

= \int_{0}^{3} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{0}^{3}

= [\frac{u ^{3}}{3}]_{0}^{3}

Compute the boundaries:

3

= 3

x \to \infty lim (x - 3 x^{4})

11 x - \frac{8}{x}

\int \frac{1}{y ^{6}} - \frac{9}{y} d y

(4 a + 1)^{2}

y^{^{''}} + 4 y^{^{'}} = 10 e^{t}

What is the integral from 1 to 2 of xsqrt(x^2-1) ?
The integral from 1 to 2 of xsqrt(x^2-1) is square root of 3