y^{''}+25y=cos(4t)

Lösung

y^{^{''}} + 25 y = cos (4 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{1}{9} cos (4 t)

Schritte zur Lösung

y^{''} (t) + 25 y = cos (4 t)

Solve linear ODE:

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{1}{9} cos (4 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{1}{9} cos (4 t)

n = 1 \sum \infty \frac{( n )}{2 ^{n}}

t an g e n t (x + 2)^{2} + (y - 3)^{2} = 37, (- 1, - 3)

\frac{d}{d x} (\frac{x ^{2} - 2}{x ^{3} + 3 x ^{2}})

d er i v a t i v e y = \frac{x + x ^{3}}{x ^{2}}

d er i v a t i v e f (x) = 7 - 2 x