18xy^'-2y=-(x^2)/(y^{17)}

解答

18 x y^{^{'}} - 2 y = - \frac{x ^{2}}{y ^{17}}

y = 18 - ln (x) x^{2} + c_{1} x^{2}, y = - 18 - ln (x) x^{2} + c_{1} x^{2}

求解步骤

18 x y^{'} (x) - 2 y = - \frac{x ^{2}}{y ^{17}}

求解贝努力方程:

y = 18 - ln (x) x^{2} + c_{1} x^{2}, y = - 18 - ln (x) x^{2} + c_{1} x^{2}

y = 18 - ln (x) x^{2} + c_{1} x^{2}, y = - 18 - ln (x) x^{2} + c_{1} x^{2}

x \to 0 lim (\frac{4 ^{x} - 1 1 ^{x}}{x})

\int \frac{x ^{2}}{( 1 - x ^{2} ) ^{2}} d x

\frac{d}{d x} (\frac{2}{x ^{2}} - \frac{3}{x ^{\frac{1}{3}}})

f (t) = cos (t)

d er i v a t i v e f (x) = (4 x + 2)^{- 1}