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人気のある微分積分 >

derivative t^2+2sqrt(t)+50

解

導関数

t^{2} + 2 t + 50

解

2 t + \frac{1}{t}

解答ステップ

\frac{d}{d t} (t^{2} + 2 t + 50)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{2}) + \frac{d}{d t} (2 t) + \frac{d}{d t} (50)

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (2 t) = \frac{1}{t}

\frac{d}{d t} (50) = 0

= 2 t + \frac{1}{t} + 0

簡素化

= 2 t + \frac{1}{t}

グラフ

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